Examtut

I hope this post will guide you to calculate VLSM very shortly. Also you don’t have to remember binary for every number except subnet mask. I take an IP address, for example: 192.168.100.40 /27 Step 1 : Subnet Mask Step 2 : Network Address and Broadcast Address Fill first 3 octets with IP Address. Now the first number of the block is Network Address and Last number of block is Broadcast Address. Step 3 : Valid IP Range Step 4 : Number of Hosts

Internet Protocol version 4 (IPv4) 32 bit address Example : 11000000 10101000 01100100 00000001 Divided into 4 groups So each group contains 8 bits. To separate groups we use PERIODS Example : 11000000 . 10101000 . 01100100 . 00000001 The format of IP address is dotted decimals We have to convert those binary bits in numbers (decimals). Example : 192 . 168 . 100 . 1 Starting number of each group must be 00000000 (0) Ending number of each group must be 11111111 (255). Classes of IP Address How to Find Class of an IP Address? Class Range Size Hosts A 1 – 126 Large 16,777,214 B 128 – 191 Medium 65,534 C 192 – 223 Small 254 D 224 – 239 Res...

Which of the following is a characteristic of full-duplex communication? A.  It is a CSMA/CD network. B.  It is a CSMA/CA network. C.  It is point-to-point only. D.  Hub communication is done via full duplex. Answer: C. It is point-to-point only. Explanation: The meaning of full duplex in computer network simply refers to a device can send and receive data without collision. Whereas Half duplex refers a device can either send or receive data. But it cannot do both at the same time. CSMA/CD (Carrier Sense Multiple Access with Collision Detection) a set of rules determining how network devices respond when two devices attempt to use a data channel simultaneously (called a collision). CSMA/CA (Carrier Sense Multiple Access/Collision Avoidance) is a protocol for carrier transmission in 802.11 networks. Unlike CSMA/CD (Carrier Sense Multiple Access/Collision Detect) which deals wit...

Refer to the exhibit. Switch-1 needs to send data to a host with a MAC address of 00b0.d056.efa4. What will Switch-1 do with this data? A.  Switch-1 will drop the data because it does not have an entry for that MAC address. B.  Switch-1 will forward the data to its default gateway. C.  Switch-1 will flood the data out all of its ports except the port from which the data originated. D.  Switch-1 will send an ARP request out all its ports except the port from which the data originated. Answer: C. Switch-1 will flood the data out all of its ports except the port from which the data originated. Explanation: When a switch received a frame it will check the destination mac-address of frame with its mac-address-table. If that particular mac-address found, then data will send to the interface where that mac-address associated. But if no interface is associated with that mac-address, then it will broadcast the...

Refer to the exhibit. Which switch provides the spanning-tree designated port role for the network segment that services the printers? A.  Switch1 B.  SWitch2 C.  Switch3 D.  Switch4 Answer : C. Switch3 Explanation: We must find which switch has designated port that connected to Printers using Hub. Check the image below. Both switches has default Bridge Priority of 32768. Second Switch3 MAC address (0010.7bcc.733a) is lower than Switch4 MAC address (0010.7bcc.7347). Then Switch3’s interface will be play a role of designated port .

This task requires you to use the CLI of Sw-AC3 to answer five multiple-choice questions. This does not require any configuration. To answer the multiple-choice questions, click on the numbered boxes in the right panel. There are five multiple-choice questions with this task. Be sure to answer all five questions before leaving this item. Question 1: What interface did Sw-AC3 associate with source MAC address 0010.5a0c.ffba ? a.    Fa0/1 b.    Fa0/3 c.    Fa0/6 d.    Fa0/8 e.    Fa0/9 f.    Fa0/12 Explanation: We need find out a device that connected to Sw-AC3 with MAC-Address (0010.5a0c.ffba). Command: show mac-address-table If this command not works try show mac address-table Find the port name that has mac-address (0010.5a0c.ffba). Answer : D. Fa0/8 Question 2: What ports on...

RouterA is unable to reach RouterB. Both routers are running IOS version 12.0. After reviewing the command output and graphic, what is the most likely cause of the problem? A. incorrect bandwidth configuration B. incorrect LMI configuration C. incorrect map statement D. incorrect IP address Answer : C Explanation: The frame-relay command was not properly configured! The Command should be frame-relay map ip 172.16.100.1 100 broadcast

The network administrator needs to address seven LANs. RIP version 1 is the only routing protocol in use on the network and subnet-zero is not being used. What is the maximum number of usable IP addresses that can be supported on each LAN if the organization is using one class C address block? A. 6 B. 8 C. 14 D. 16 E. 30 F. 32 Answer : E Explaination: We need 7 LANs also subnet-zero (1st subnet must be not be included). So we need 7 subnets, then the appropriate mask will be 255.255.255.224. For example: assume that our IP address will be on 192.168.100.0 network. Then the subnet would be 192.168.100.0 192.168.100.32 192.168.100.64 192.168.100.96 192.168.100.128 192.168.100.160 192.168.100.192 192.168.100.224 For each subnet it will have 30 usable ip addresses. Refer to the question, the below is the topology of the network 7 network

The network administrator has found the following problem. The remote networks 172.16.10.0, 172.16.20.0, and 172.16.30.0 are accessed through the Central router's serial 0/0 interface. No users are able to access 172.16.20.0. After reviewing the command output shown in the graphic, what is the most likely cause of the problem? A. no gateway of last resort on Central B. Central router's not receiving 172.16.20.0 update C. incorrect static route for 172.16.20.0 D. 172.16.20.0 not located in Central's routing table Answer : C Explanation : From the above CLI output we can figure out the topology. Also check the configuration error in Exhibit. If we use 172.16.20.0 to route to 172.16.150.15, then the packet will route back. To clear this error we have to use #no ip route 172.16.20.0 255.255.255.0 172.16.150.15 command in configuration mode.

Workstation A has been assigned an IP address of 192.0.2.24/28. Workstation B has been assigned an IP address of 192.0.2.100/28. The two workstations are connected with a straight- through cable. Attempts to ping between the hosts are unsuccessful. What are two things that could be attempted that would allow communications between the hosts? (Choose two.)   A. Replace the straight-through cable with a crossover cable. B. Change the subnet mask of the hosts to /25. C. Change the subnet mask of the hosts to /26. D. Change the address of Workstation A to 192.0.2.15. E. Change the address of Workstation B to 192.0.2.111. Answer : A and B Explanation: A: Host to Host communication needs crossover cable. Both hosts using 190.0.2.0 network with /28 mask. Subnet Mask : 255.255.255.240 = 256 – 240 = 16 Network Address Broadcast Address 0 15 ...

Your ISP has given you the address 223.5.14.6/29 to assign to your router’s interface. They have also given you the default gateway address of 223.5.14.7. After you have configured the address, the router is unable to ping any remote devices. What is preventing the router from pinging remote devices? A. The default gateway is not an address on this subnet. B. The default gateway is the broadcast address for this subnet. C. The IP address is the broadcast address for this subnet. D. The IP address is an invalid class D multicast address. Answer : B Explanation: IP Address : 223.5.14.6 /29 Subnet Mask : 255.255.255.248 Subtract 248 from 256. 256 – 248 = 8. Network Address : 223.5.14.0 Broadcast Address : 223.5.14.7

A. 131.1.123.30 B. 131.1.123.31 C. 131.1.123.32 D. 131.1.123.33 Answer : A Explanation: IP Address: 131.1.123.0 /27 Subnet Mask (Binary) : 11111111 . 11111111 . 11111111 . 1110000 Subnet Mask : 255.255.255.224 Lets subtract 224 from 256. 256 - 224 = 32. Network Address Broadcast Address 0 31 32 63 64   The last IP address will be 131.1.123.30. Network Address : 131.1.123.0 Broadcast Address : 131.1.123.31 Valid IP Range : 131.1.123.1 to 131.1.123.30 Maximum Hosts Available : 2 5 -2 = 30

A dental firm is redesigning the network that connects its three locations. The administrator gave the networking team 192.168.164.0 to use for addressing the entire network. After subnetting the address, the team is ready to assign the addresses. The administrator plans to configure ip subnet-zero and use RIP v2 as the routing protocol. As a member of the networking team, you must address the network and at the same time conserver unused addresses for future growth. With those goals in mind, drag the host addresses on the left to the correct router interface. Once of the routers is partially configured. Move your mouse over a router to view its configuration. Not all of the host addresses on the left are necessary. How to Find? Step 1: Find the Number of Hosts for each subnet mask. Trust me! If you practice and practice, then the below formula will never go out of your head. Network Bits Host Bits Formula Max. no....

After adding Interior router, no routing updates are being exchanged between Perimeter and the new location. All other inter connectivity and Internet access for the existing locations of the company are working properly. The Task is to identify the fault(s) and correct the router configurations to provide full connectivity between the routers. Access to the router CLI can be gained by clicking on the appropriate host. All passwords on all routers are cisco. IP Address are listed in the chart below Steps Remove invalid Autonomous System Number and add the correct Autonomous System Number Interior router. The Autonomous System Number is found in the topology: Add the network address of Fa0/0 interface of Perimeter router in EIGRP configuration. Because EIGRP neighbor relationship is not possible without the configuring connected interfaces. Answer Commands First we shou...