A. 131.1.123.30
B. 131.1.123.31
C. 131.1.123.32
D. 131.1.123.33
Answer : A
Explanation:
IP Address: 131.1.123.0 /27
Subnet Mask (Binary) : 11111111 . 11111111 . 11111111 . 1110000
Subnet Mask : 255.255.255.224
Lets subtract 224 from 256.
256 - 224 = 32.
Network Address | Broadcast Address |
0 | 31 |
32 | 63 |
64 |
The last IP address will be 131.1.123.30.
Network Address : 131.1.123.0
Broadcast Address : 131.1.123.31
Valid IP Range : 131.1.123.1 to 131.1.123.30
Maximum Hosts Available : 25-2 = 30
Comments
Post a Comment